4u^2+38u+34=0

Solution for 4u^2+38u+34=0 equation:

4u^2+38u+34=0

a = 4; b = 38; c = +34;
Δ = b2-4ac
Δ = 382-4·4·34
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(38)-30}{2*4}=\frac{-68}{8}
=-8+1/2
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(38)+30}{2*4}=\frac{-8}{8}
=-1
$